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In the vx__voxelize function, the vx__aabb_center function is used to obtain the center point of an AABB by calculating (saabb.min + saabb.max) / 2. However, this is equivalent to ((xyz - hvs) + (xyz + hvs)) / 2, which simplifies to xyz.
Is there a specific reason for using vx__aabb_center to get the AABB center rather than using xyz directly?
Lines 630 to 637 in f6ee9cf
| vx_vertex_t vx__aabb_center(vx_aabb_t* a) | |
| { | |
| vx_vertex_t boxcenter = a->min; | |
| vx__vec3_add(&boxcenter, &a->max); | |
| vx__vec3_multiply(&boxcenter, 0.5f); | |
| return boxcenter; | |
| } |
Lines 756 to 769 in f6ee9cf
| for (float x = aabb.min.x; x <= aabb.max.x; x += vs.x) { | |
| for (float y = aabb.min.y; y <= aabb.max.y; y += vs.y) { | |
| for (float z = aabb.min.z; z <= aabb.max.z; z += vs.z) { | |
| vx_aabb_t saabb; | |
| saabb.min.x = x - hvs.x; | |
| saabb.min.y = y - hvs.y; | |
| saabb.min.z = z - hvs.z; | |
| saabb.max.x = x + hvs.x; | |
| saabb.max.y = y + hvs.y; | |
| saabb.max.z = z + hvs.z; | |
| vx_vertex_t boxcenter = vx__aabb_center(&saabb); | |
| vx_vertex_t halfsize = vx__aabb_half_size(&saabb); |
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